Second largest element in an array GFG

 package com.company;

public class Array3 {
    //Efficient solution
    public static int second(int[] arr, int n) {
        int res = -1;
        int largest = 0;
        for (int i = 1; i < n; i++) {
            if (arr[i] > arr[largest]) {
                res = largest;
                largest = i;
            } else if (arr[i] != arr[largest]) {
                if (res == -1 || arr[i] > arr[res]) {
                    res = i;
                }
            }
        }
        return res;
    }
//    Naive solution

    private static int firstLargest(int[] arr) {
        int res = 0;
        for (int i = 1; i < arr.length; i++) {
            if (arr[i] > arr[res]) {
                res = i;
            }
        }
        return res;
    }

    //    Finding the index of second-largest number
//    This solution is valid when there is no repetition of element in array MY SOLUTION
    public static int getSecondLargest(int[] arr) {
        int res = -1;
        int a = firstLargest(arr);
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] != arr[a]) {
                if (res == -1) {
                    res = i;
                } else if (arr[i] > arr[res]) {
                    res = i;
                }
            }
        }
        return res;
    }

    public static void main(String[] args) {
        int[] array = {1, 1, 1};
        System.out.println(second(array,3));
    }
}